## Partition List

Challenge Given the head of a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. The order of the initial linked list must be preserved. Solution from copy import deepcopy class Solution: def add_to_list(self, head, node,x): node.next = None if head is None and node.val < x: self.left_part = node self.left_tail = node return elif head is None and node....

August 2, 2021 · 1 min · Nolan

## Remove Duplicates From an Unsorted Linked List

Challenge Given the head of a linked list, find all the values that appear more than once in the list and delete the nodes that have any of those values. Return the linked list after the deletions. e.g 1 -> 2 ->3 ->2 returns 1 -> 3 Solution # Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def print_list(self, head): tmp = head while tmp: print(tmp....

March 12, 2021 · 1 min · Nolan