## Partition List

Challenge Given the head of a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. The order of the initial linked list must be preserved. Solution from copy import deepcopy class Solution: def add_to_list(self, head, node,x): node.next = None if head is None and node.val < x: self.left_part = node self.left_tail = node return elif head is None and node....